A hockey ball of mass 200 gram travelling at 10 m/s is struck by a hockey stick so as to return it along with original path with a velocity at 5 m/s . Calculate the change of momentum Orchid in the motion of the hockey Ball by the force applied by the hockey stick.

How did the change of momentum have postive sign?

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Solution

he Mass of Hockey ball, m = 200 g = 0.2 kg

Initial velocity, u = 10 ms⁻¹

Final velocity, v = −5ms⁻¹

Initial momentum, p₁ =mu = 0.2 ×10 = 2 kg ms⁻¹

Final momentum, p₂ =mu = 0.2 ×(−5) = &minus1 kg ms⁻¹

∴ Change in momentum =p₂−p₁

=&minus1 kg ms⁻¹ − 2 kg ms⁻¹

=− 3 kg ms⁻¹

The negative sign shows a change in direction of hockey ball, along the return path after strike

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A hockey ball of mass 200 g travelling at 10 m s⁻¹ is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s⁻¹. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Q. Question 13
A hockey ball of mass 200 g travelling at

10 m s^{- 1}

is struck by a hockey stick so as to return it along its original path with a velocity at

5 m s^{- 1}

. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Q. A hockey ball of mass

50 g

travelling at

20 m / s

is struck by a hockey stick. So as to return it along its original path with a velocity at

20 m / s

. Its change in momentum occured in the motion of the hockey ball by the force applied by the hockey stick:

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he Mass of Hockey ball, m	= 200 g = 0.2 kg
Initial velocity, u	= 10 ms⁻¹
Final velocity, v = −5ms⁻¹
Initial momentum, p₁	=mu = 0.2 ×10 = 2 kg ms⁻¹
Final momentum, p₂	=mu = 0.2 ×(−5) = &minus1 kg ms⁻¹
∴ Change in momentum	=p₂−p₁
	=&minus1 kg ms⁻¹ − 2 kg ms⁻¹
	=− 3 kg ms⁻¹
The negative sign shows a change in direction of hockey ball, along the return path after strike