A hockey ball of mass $50 g$ travelling at $20 m / s$ is struck by a hockey stick. So as to return it along its original path with a velocity at $20 m / s$ . Its change in momentum occured in the motion of the hockey ball by the force applied by the hockey stick:

- 1 k g m / s

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- 2 k g m / s

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0.2 k g m / s

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- 0.5 k g m / s

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Solution

The correct option is B $- 2 k g m / s$
Given : $m = 0.05$ kg $u = 20$ m/s $v = - 20$ m/s
Change in momentum $Δ P = m (v - u) = 0.05 (- 20 - (20)) = 0.05 \times - 40 = - 2$ $k g$ $m / s$

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Q. A hockey ball of mass 200 g travelling at 10 m s⁻¹ is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s⁻¹. Calculate the magnitude of change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Q. Question 13
A hockey ball of mass 200 g travelling at

10 m s^{- 1}

is struck by a hockey stick so as to return it along its original path with a velocity at

5 m s^{- 1}

. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

A hockey ball of mass 200 gram travelling at 10 m/s is struck by a hockey stick so as to return it along with original path with a velocity at 5 m/s . Calculate the change of momentum Orchid in the motion of the hockey Ball by the force applied by the hockey stick.

How did the change of momentum have postive sign?

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A hockey ball of mass 50 g travelling at 20 m/s is struck by a hockey stick. So as to return it along its original path with a velocity at 20m/s . Its change in momentum occured in the motion of the hockey ball by the force applied by the hockey stick:

The correct option is B −2 kg m/sGiven : m=0.05 kg u=20 m/s v=−20 m/s Change in momentum ΔP=m(v−u)=0.05(−20−(20))=0.05×−40=−2 kg m/s

A hockey ball of mass $50 g$ travelling at $20 m / s$ is struck by a hockey stick. So as to return it along its original path with a velocity at $20 m / s$ . Its change in momentum occured in the motion of the hockey ball by the force applied by the hockey stick:

The correct option is B $- 2 k g m / s$
Given : $m = 0.05$ kg $u = 20$ m/s $v = - 20$ m/s
Change in momentum $Δ P = m (v - u) = 0.05 (- 20 - (20)) = 0.05 \times - 40 = - 2$ $k g$ $m / s$