A hod body placed in air is cooled down according to Newton's Law of Cooling, the rate of decrease of temperature being $k$ times the temperature difference from the surrounding. Starting from $t = 0$ , find the time in which the body will loose half the maximum heat it can loose.

\frac{l n 3}{K}

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\frac{l n 2}{K}

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\frac{2 l n 2}{K}

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\frac{l n 2}{2 K}

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Solution

The correct option is B $\frac{l n 2}{K}$ .

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Q. A hot body placed in the air is cooled according to Newton's law of cooling. The rate of decrease of the temperature being k times the temperature difference from the surroundings, starting from t = 0, In

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A hod body placed in air is cooled down according to Newton's Law of Cooling, the rate of decrease of temperature being k times the temperature difference from the surrounding. Starting from t=0, find the time in which the body will loose half the maximum heat it can loose.

The correct option is B ln2K.

A hod body placed in air is cooled down according to Newton's Law of Cooling, the rate of decrease of temperature being $k$ times the temperature difference from the surrounding. Starting from $t = 0$ , find the time in which the body will loose half the maximum heat it can loose.

The correct option is B $\frac{l n 2}{K}$ .