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Question

A hoist operated by an electric motor has a mass of 500 kg. It raises a load of 300 kg vertically at a steady speed of 0.2 m/s. Frictional resistance can be taken to be constant at 1200 N. What is the power required?

A
1.51 kW
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B
1.81 kW
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C
2.01 kW
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D
1.61 kW
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Solution

The correct option is B 1.81 kW

Total mass = m = 800 kg
Weight = 800 × 9.81
= 7848 N

Total force = 7848 + 1200
= 9048 N

Power = force × speed
= 9048 × 0.2
= 1810 W
= 1.81 kW


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