A hole diffuses from the P-side to the N-side in a P-N junction. This means that-

A bond is broken on the $N -$ side and the electron free from the bond jumps to the conduction band

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A conduction electron on the $P -$ side jumps to a broken bond to complete it

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A bond is broken on the $N -$ side and the electron free from the bond jumps to a broken bond on the $P -$ side to complete it.

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A bond is broken on the $P -$ side and the electron free from the bond jumps to a broken bond on the $N -$ side complete it

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Solution

The correct option is C
A bond is broken on the $N -$ side and the electron free from the bond jumps to a broken bond on the $P -$ side to complete it.

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Q. A hole diffuses from the p-side to the n-side in a p-n junction. This means that
(a) a bond is broken on the n-side and the electron freed from the bond jumps to the conduction band
(b) a conduction electron on the p-side jumps to a broken bond to complete it
(c) a bond is broken on the n-side and the electron freed from the bond jumps to a broken bond on the p-side to complete it
(d) a bond is broken on the p-side and the electron freed from the bond jumps to a broken bond on the n-side to complete it.

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A hole diffuses from the P-side to the N-side in a P-N junction. This means that-

The correct option is C A bond is broken on the N−side and the electron free from the bond jumps to a broken bond on the P−side to complete it.

The correct option is C
A bond is broken on the $N -$ side and the electron free from the bond jumps to a broken bond on the $P -$ side to complete it.