A hole diffuses from the P−side to the N−side in a P−N junction. This means that
A
A bond is broken on the N−side and the electron free from the bond jumps to the conduction band
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B
A conduction electron on the P−side jumps to a broken bond to complete it
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C
A bond is broken on the N−side and the electron free from the bond jumps to a broken bond on the P−side to complete it.
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D
A bond is broken on the P−side and the electron free from the bond jumps to a broken bond on the N−side complete it
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Solution
The correct option is C
A bond is broken on the N−side and the electron free from the bond jumps to a broken bond on the P−side to complete it.
Whenever a hole diffuses from the P−side to the N−side in a P−N junction. A bond is broken on the N−side and the electron free from the bond jumps to a broken bond on the P−side to complete it. Thus maintaining the balance.