Question

A hole is specified as ${25}^{\begin{array}{c}+0.03\\ +0.02\end{array}}$ mm. The mating shaft has a transition fit with maximum interference of 20 microns. The tolerance on the shaft is 50 microns. The maximum clearance between the hole and shaft is ___________microns.

• A. 30
• B. 40
• C. 10
• D. 20

Answer 1

The correct option is B 40



$\text{Maximum interference = L.L of hole - U.L of shaft}$

$-0.02=25.02-\text{x}$

$\Rightarrow \text{x = U.L of shaft =25.04 mm}$

$\text{Tolerance of shaft = U.L of shaft -L.L of shaft}$

$0.05=25.04\text{mm}-\text{y}$

$\Rightarrow \text{y = L.L of shaft = 24.99 mm}$

$\text{Maximum clearance = U.L of hole - L.L of shaft}$

$=25.03-24.99=40\text{microns}$