Question

A hole is specified as ${40}^{\begin{array}{c}+0.050\\ +0.000\end{array}}mm$. The mating shaft has a clearance fit with a minimum clearance of 0.01 mm. The tolerance on the shaft is 0.04 mm. The maximum clearance in mm between the hole and the shaft is

• A. $0.04$
• B. $0.05$
• C. $0.11$
• D. $0.10$

Answer 1

The correct option is D $0.10$

$\text{Given data:}$

$\text{Low limit of hole}=40.000mm$

$\text{High limit of hole}=40.000+0.050$

$=40.050mm$

$\text{High limit of shaft}=40.000-0.01$

$=39.990mm$

$\text{Low limit of shaft}=39.990-0.04=39.950mm$


$\text{Maximum clearance = 40.050 - 39.950 = 0.10 mm}$