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Strength of Materials
Strength of Shafts in Torsion
A hollow circ...
Question
A hollow circular shaft has an outer diameter of 100 mm and inner diameter of 50 mm. If the allowable shear stress is 125 MPa, the maximum torque(in kN-m) that the shaft can resist is .
23
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Solution
The correct option is
A
23
τ
a
l
l
o
w
a
b
l
e
=
125
N
m
m
2
T
m
a
x
J
=
τ
a
l
l
o
w
a
b
l
e
R
⇒
T
m
a
x
.
=
125
50
×
(
π
32
×
(
100
4
−
50
4
)
)
=
23009711.82
N-mm
=
23.00
×
10
+
6
N-mm
=
23
kN-m
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