A hollow cylinder of mass M and radius R is pulled by a horizontal force F acting at its centre of mass on a horizontal surface where the coefficient of friction is μ.
If hollow cylinder is performing pure rolling then frictional force f will be :
A
F
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B
F2
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C
F3
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D
2F
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Solution
The correct option is BF2 There are two horizontal force on the hollow cylinder. One is friction force and other is F, in opposite direction. Taking the torque around top point ( there will be one pseudo force but that would pass via top point so there will no effect of that force in torque) . Then, net torque around top point =0 F×R−f×2R=0 f=F2