A hollow metal of mass $180.6 g$ contains cavity of volume $2.5 c m^{3}$ . This metal when placed in water displaces $24 c c$ of water. Find the specific gravity of metal

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Solution

Volume of sphere is 24cc
Volume of cavity= $2.5 c m^{3}$
volume of metal $V = 24 - 2.5 = 21.5 c m^{3}$
No we know that density = $\frac{M a s s}{V o l u m e}$
So $ρ = \frac{180.6}{21.5}$
$ρ = 8.4 g / c m^{3}$

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A hollow metal of mass 180.6 g contains cavity of volume 2.5 cm3. This metal when placed in water displaces 24 cc of water. Find the specific gravity of metal

Volume of sphere is 24ccVolume of cavity=2.5cm3volume of metal V=24−2.5=21.5cm3No we know that density =MassVolumeSo ρ=180.621.5ρ=8.4g/cm3

A hollow metal of mass $180.6 g$ contains cavity of volume $2.5 c m^{3}$ . This metal when placed in water displaces $24 c c$ of water. Find the specific gravity of metal

Volume of sphere is 24cc
Volume of cavity= $2.5 c m^{3}$
volume of metal $V = 24 - 2.5 = 21.5 c m^{3}$
No we know that density = $\frac{M a s s}{V o l u m e}$
So $ρ = \frac{180.6}{21.5}$
$ρ = 8.4 g / c m^{3}$