A hollow metal pipe is 63 cm long. The inner diameter of cross-section is 4 cm and the outer diameter is 4.8 cm. Find the total surface area of the pipe.

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Solution

The outer radius is $4.8 c m$
The height of pipe $63 c m$
The surface area of pipe is $2 π r h 2 \frac{22}{7} \times 4.8 \times 63 18 \times 22 \times 4.8 = 1900.8 c m^{2}$

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