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Standard XII

Chemistry

Kinetic Theory of Gases

A hollow meta...

Question

A hollow metal sphere of 150 mm inside diameter is weighed on a precision beam balance when evacuated and again after being filled to 1750 kPa with a unkown gas. The difference in mass is 0.0050 kg and the temperature is $25^{\circ} C$ , Which gas is this, Assume it to be a pure substance ?

Hydrogen

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Helium

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Oxygen

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Neon

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Solution

The correct option is B Helium
$m = 0.0050 k g P = 1750 \times 10^{3} P a T = 298 K V = \frac{π}{6} \times (0.15)^{3}$
From ideal gas equation
$M = \frac{m ¯ R T}{P V} = \frac{0.0050 \times 8314 \times 298}{1750 \times 10^{3} \times \frac{π}{6} \times (0.15)^{3}} = 4$

So the gas is Helium

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A hollow metal sphere of 150 mm inside diameter is weighed on a precision beam balance when evacuated and again after being filled to 1750 kPa with a unkown gas. The difference in mass is 0.0050 kg and the temperature is 25∘C, Which gas is this, Assume it to be a pure substance ?

The correct option is B Heliumm=0.0050 kgP=1750×103PaT=298KV=π6×(0.15)3 From ideal gas equation M=m¯RTPV=0.0050×8314×2981750×103×π6×(0.15)3=4 So the gas is Helium

A hollow metal sphere of 150 mm inside diameter is weighed on a precision beam balance when evacuated and again after being filled to 1750 kPa with a unkown gas. The difference in mass is 0.0050 kg and the temperature is $25^{\circ} C$ , Which gas is this, Assume it to be a pure substance ?

The correct option is B Helium
$m = 0.0050 k g P = 1750 \times 10^{3} P a T = 298 K V = \frac{π}{6} \times (0.15)^{3}$
From ideal gas equation
$M = \frac{m ¯ R T}{P V} = \frac{0.0050 \times 8314 \times 298}{1750 \times 10^{3} \times \frac{π}{6} \times (0.15)^{3}} = 4$

So the gas is Helium