Question

A hollow object of volume V is immersed in a tank. the object is tied to the bottom of the tank by two wires which make an angle ${30}^0$ with the horizontal as shown in figure. the object would float if it was set free and one fourth volume is immersed in liquid of density $P_0$. the tension in the wire

• A. $\frac{V{p}_{0}g}{4}$
• B. $\frac{3V{p}_{0}g}{4}$
• C. $\frac{5V{p}_{0}g}{4}$
• D. $V{p}_{0}g$

Answer 1

The correct option is D $V{p}_{0}g$

Buoyant force ( F )= Submerged part of the body $\times$ density of liquid $\times$ acceleration due to gravity

Here$,F=V\times P\times g$

The buoyant force acts vertically upwards on the object and buoyant force $=V{P}_{0}g$

Hence,

option $\left(D\right)$ is correct answer.