A hollow sphere is filled with water through a small hole in it. It is hung by a long thread and made to oscillate. As the water slowly flows out of the hole at the bottom, the period of oscillation will

increase

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decrease

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remain the same

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first increase and then decrease

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Solution

The correct option is D first increase and then decrease
$T = 2 π \sqrt{\frac{l}{g}}$
As the water flows out, the centre of mass of the bob with water shifts downwards and hence increases. Once all the water is completely drained out, the centre of mass shifts back to its initial position and then decreases.

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A hollow sphere is filled with water through a small hole in it. It is hung by a long thread and made to oscillate. As the water slowly flows out of the hole at the bottom, the period of oscillation will

The correct option is D first increase and then decreaseT=2π√lg As the water flows out, the centre of mass of the bob with water shifts downwards and hence increases. Once all the water is completely drained out, the centre of mass shifts back to its initial position and then decreases.