A hollow sphere of internal and external diameters 4 cm and 8 cm respectively is melted into a cone of base diameter 8 cm. Find the height of the cone.
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Solution
•If solid of one shape is converted into solid of another shape, then Total volume of the solid to be converted = Total volume of the solid into which the given solid is to be converted.
SOLUTION : Given : Internal diameter of hollow sphere(d)= 4 cm. Internal radius of hollow sphere (r) = 4/2= 2 cm external diameter of hollow sphere (D) = 8 cm. external radius of hollow sphere( R )= 8/2= 4 cm.
Volume of the Hollow sphere = 4/3π(R³ - r³) Volume of the Hollow sphere = 4/3π(4³ - 2³) Volume of the Hollow sphere = 4/3π(64 - 8) Volume of the Hollow sphere = 4/3π(56) cm³
Diameter of the cone(d1) = 8 cm radius of the cone( r1)= 8/2 = 4 cm
Let the height of the cone be h cm. Volume of the cone = ⅓ πr1²h = ⅓ π × 4² × h = 16πh/3
Volume of the cone = Volume of the hollow sphere 16πh/3 = 4/3π(56) 16h = 4 ×56 h = (4 × 56)/16 h = 56/4 = 14 cm