wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A hollow sphere of internal and external diameters 4 cm and 8 cm respectively is melted into a cone of base diameter 8 cm. Find the height of the cone.

Open in App
Solution

•If solid of one shape is converted into solid of another shape, then Total volume of the solid to be converted = Total volume of the solid into which the given solid is to be converted.

SOLUTION :
Given : Internal diameter of hollow sphere(d)= 4 cm.
Internal radius of hollow sphere (r) = 4/2= 2 cm
external diameter of hollow sphere (D) = 8 cm.
external radius of hollow sphere( R )= 8/2= 4 cm.

Volume of the Hollow sphere = 4/3π(R³ - r³)
Volume of the Hollow sphere = 4/3π(4³ - 2³)
Volume of the Hollow sphere = 4/3π(64 - 8)
Volume of the Hollow sphere = 4/3π(56) cm³

Diameter of the cone(d1) = 8 cm
radius of the cone( r1)= 8/2 = 4 cm

Let the height of the cone be h cm.
Volume of the cone = ⅓ πr1²h
= ⅓ π × 4² × h = 16πh/3

Volume of the cone = Volume of the hollow sphere
16πh/3 = 4/3π(56)
16h = 4 ×56
h = (4 × 56)/16
h = 56/4 = 14 cm

Hence, the height of the cone is 14 cm.


flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Shape Conversion of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon