A hollow sphere of internal and external diameters $4 c m$ and $8 c m$ respectively is melted into a cone of base diameter $8 c m$ . Calculate the height of the cone.

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Solution

$\frac{4}{3} π (R_{e}^{3} - R_{i}^{3}) = \frac{1}{3} π r^{2} h$

$\Rightarrow h = \frac{4 (4^{3} - 2^{3})}{4^{2}} = 14 c m$

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A hollow sphere of internal and external diameters $4 c m$ and $8 c m$ respectively is melted into a cone of base diameter $8 c m$ . Calculate the height of the cone.

$\frac{4}{3} π (R_{e}^{3} - R_{i}^{3}) = \frac{1}{3} π r^{2} h$

$\Rightarrow h = \frac{4 (4^{3} - 2^{3})}{4^{2}} = 14 c m$