A hollow sphere rolls down a 300 incline of length 6m without slipping. The speed of centre of mass at the bottom of plane is
Since the sphere rolls down without slipping, it is performing pure rolling motion
Hence v=Rw
Applying conservation of energy (Let the mass of sphere be m)
Ei=mgh(h=6sin30 the height of top of incline from ground)
Ei=m10(6sin30)
Ei=30m
Ef=1/2mv2+1/2Iw2 ( I is the moment of inertia I=2/3 MR2 for hollow sphere)
Ef=1/2mR2w2+1/2(2/3mR2)w2
Ef=5/6mR2w2
Solving Ei=Ef you will have
R2w2=36
Rw=6=vcm
=6ms−1