A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field

is constant inside the tube

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increases linearly from the axis to the surface

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is zero just outside the tube.

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is zero at the axis

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Solution

The correct options are
A is constant inside the tube
D is zero at the axis
If $r < d$ then,
$\oint B . d l = \frac{I}{μ}$
If $r < d$ , $I_{e n c l o s e d} = 0$
$\to B .2 π r = 0$
$\to B = 0$ and constant for $r < d$

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Similar questions

Q. A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field
(a) increases linearly from the axis to the surface
(b) is constant inside the tube
(c) is zero at the axis
(d) is zero just outside the tube.

A thin but long, hollow, cylindrical tube of radius r carries a current i along its length. Find the magnitude of the magnetic field at a distance $r / 2$ from the surface (a) inside the tube (b) outside the tube.

A long, cylindrical tube of inner and outer radii a and b carries a current i distributed uniformly over its cross section. Find the magnitude of the magnetic field at a point (a) just inside the tube (b) just outside the tube.

Q. STATEMENT - 1 : A uniformly distributed direct current flows through a solid long metallic cylinder along its length. It produces magnetic field only outside the cylinder .
STATEMENT - 2 : A thin long cylindrical tube carrying uniformly distributed direct current along its length does not produce a magnetic field inside it.Moreover, a solid cylinder can be supposed to be made up of many thin cylindrical tubes.

Q. Match the column

I

with column

I I

Column $I$	Column $I I$
$a .$ Magnetic field inside a long straight solenoid is	$p .$ not constant
$b .$ Magnetic field inside a toroidal solenoid is	$q .$ zero
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A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field

The correct options are A is constant inside the tube D is zero at the axisIf r<d then,∮B.dl=IμIf r<d, Ienclosed=0→B.2πr=0→B=0 and constant for r<d

The correct options are
A is constant inside the tube
D is zero at the axis
If $r < d$ then,
$\oint B . d l = \frac{I}{μ}$
If $r < d$ , $I_{e n c l o s e d} = 0$
$\to B .2 π r = 0$
$\to B = 0$ and constant for $r < d$