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Question

A homogeneous block of mass m, width b and height h is resting on a rough horizontal surface. A horizontal force F is applied to it, which makes it to move with a constant velocity. The coefficient of friction between block and surface is μ. Find the greatest height at which force F may be applied to slide the block without tipping over.
874191_4103966d832d4ef6b6b263de55336f71.png

A
b2μ
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B
2bμ
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C
bμ
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D
22bμ
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Solution

The correct option is D b2μ
To not topple the torque on it must be balanced.
Now,
F(x)=mg(b2)x=mgb2F
On balancing force
μN=Fμmg=F
So,
x=mgb2μmgx=b2μ

1152137_874191_ans_b18b8c16c17e4257ab3acfb77f3db500.png

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