You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Engineering Mechanics

Applied Force v/s Friction Force

A homogeneous...

Question

A homogeneous cubic block of side L and weight 200 N resting on a horizontal floor is acted upon by a force of 100 N at an angle of $60^{o}$ to the horizontal as shown in the figure. If the coefficient of friction is 0.3, the magnitude of the frictional force between the block and the floor is

0 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

86 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 50 N

$\sum F_{y} = 0$

$∴ N = 200 + 100 s i n 60$

The maximum value static frictional force

$f_{s} = μ N = 0.3 (200 + 100 s i n 60) \approx 86 N$

When applied force in tangential direction is less than the maximum force then the frictional force is equal to applied force.

$∴ F = 100 cos 60 = 50 N$

Suggest Corrections

Similar questions

Q. A block of mass 10 kg rests on a horizontal floor. The acceleraton due to gravity is

9.81 \frac{m}{s^{2}}

. The coefficient of static friction between the floor and the block is 0.2. A horizontal forcce of 10 N is applied on the block as shown in the figure. The magnitude of force of friction (in N) on the block is

A block of weight 200 N is pulled along a rough horizontal surface at a constant speed by a force of 100 N acting at an angle of $30^{\circ}$ above the horizontal. The coefficient of friction between the block and the surface is

A block of mass

20

k g

is acted upon by a force

F = 30

N

at an angle

53^{0}

with the horizontal in the downward direction, as shown in the figure. The coefficient of friction between the block and the horizontal surface is

0.2

. If the block remains stationary, the friction force acting on the block by the ground is

(g = 10 m / s^{2})

Q. A block of mass 1 kg lying on floor is subjected to a horizontal force given by

F = 2 s i n ω t .

The coefficient of friction between the block and the floor is 0.25

Q. A block of mass

15 kg

is acted upon by a force

25 N

at an angle

37^{\circ}

with the horizontal in a direction as shown in figure. The coefficient of static friction(

μ

) between the block and horizontal surface is

0.2

. Find the frictional force acting on the block, so that it doesn't move. Take

(g = 10 {m/s}^{2})

Join BYJU'S Learning Program

A homogeneous cubic block of side L and weight 200 N resting on a horizontal floor is acted upon by a force of 100 N at an angle of 60o to the horizontal as shown in the figure. If the coefficient of friction is 0.3, the magnitude of the frictional force between the block and the floor is

The correct option is B 50 N ∑Fy=0 ∴ N=200+100 sin 60 The maximum value static frictional force fs=μ N=0.3(200+100 sin 60)≈86 N When applied force in tangential direction is less than the maximum force then the frictional force is equal to applied force. ∴ F=100cos60=50 N

A homogeneous cubic block of side L and weight 200 N resting on a horizontal floor is acted upon by a force of 100 N at an angle of $60^{o}$ to the horizontal as shown in the figure. If the coefficient of friction is 0.3, the magnitude of the frictional force between the block and the floor is