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A homogeneous rod XY of length L and mass M is pivoted at the centre C such that it can rotate freely in the vertical plane. Initially, the rod is in the horizontal position. A blob of wax of same mass M as that of the rod falls vertically with the speed V and sticks to the rod midway between points C and Y. If the rod rotates with angular speed ω what will be angular speed in terms of V and L?

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Solution

By law of conservation of angular momentum,
Lwax about C=Iω system about C
MVL4=[ML212+M(L4)2]ωVL4=[L212+L216]ωω=12v7L

1224255_782366_ans_c494417a8e4b4788bea18244bd1b7ff8.png

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