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Standard XII

Physics

Equation of Continuity

A homogeneous...

Question

A homogeneous solid cylinder of length L $(L < H / 2)$ . Cross-sectional area A/5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L/4 ijn the denser liquid as shown in the figure. The lower density is pen to atmosphere having pressure $p_{0}$ . The density D of solid is given by

\frac{5}{4} d

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\frac{4}{5} d

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\frac{d}{5}

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Solution

The correct option is B $\frac{5}{4} d$

$Acc.to archemedes principal.$

mass cylender $=$ displace $($ lig. $_{1} + {lig}_{.2})$

$ρ v_{g} = d (\frac{3 v}{4}) g + 2 d (\frac{v}{4})$

$ρ = \frac{3 d}{4} + \frac{2 d}{4}$

$ρ = \frac{5 d}{4}$

Answer:-(A)

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The correct option is B 54d Acc.to archemedes principal. mass cylender = displace ( lig. 1+lig.2)ρvg=d(3v4)g+2d(v4)ρ=3d4+2d4ρ=5d4Answer:-(A)

The correct option is B $\frac{5}{4} d$

$Acc.to archemedes principal.$

mass cylender $=$ displace $($ lig. $_{1} + {lig}_{.2})$

$ρ v_{g} = d (\frac{3 v}{4}) g + 2 d (\frac{v}{4})$

$ρ = \frac{3 d}{4} + \frac{2 d}{4}$

$ρ = \frac{5 d}{4}$

Answer:-(A)