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Question

A hoop of radius r and mass m rotating with an angular velocity ωo is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases to slip?

A
rω03
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B
rω02
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C
rω0
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D
rω04
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Solution

The correct option is B rω02
From conservation of angular momentum
mr2ω0=mvr+mr2vr.
or
mr2ω0=2mvr
or
v=rω02
143406_31849_ans_6b0bb37e74a548a1bb4f1303e4f54769.png

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