A hoop of radius r and mass m rotating with an angular velocity ωo is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases to slip?
A
rω03
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B
rω02
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C
rω0
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D
rω04
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Solution
The correct option is Brω02 From conservation of angular momentum mr2ω0=mvr+mr2vr. or mr2ω0=2mvr or ∴v=rω02