A horizontal force acts on a body placed on a smooth horizontal table. If the force applied is $10 N$ , find the total work done when the displacement of the body is $5 m$ .

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Solution

Step 1: Given data
Force applied (F) = $10 N$
Displacement of the body (s) = $5 m$
Here angle between force and displacement is zero as they are parallel to each other hence $θ$ $= 0 °$
Step 2: Finding work done
Work $= F s \cos θ$
$= 10 \times 5 \times \cos 0 °$
$= 10 \times 5 \times 1 = 50 J$
Hence, the work done here is $50 J$

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Similar questions

A horizontal force acts on a body placed on a smooth horizontal table. If the force applied is $10 N$ , find the total work done when the displacement of the body is $5 m$ .

In the above example if the force acts at an angle of $60 °$ to the horizontal, find the work done for the same amount of displacement.

Q. A force of

10 N

acting on a body at an angle of

60^{0}

with the horizontal direction displaces the body through a distance of

2 m

along the surface of a floor. Calculate the work done. Now let the force or pull acting on the body makes an angle of

30^{0}

with the horizontal. What is the value of the force to displace the body through

2 m

along the surface of the floor?

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A horizontal force acts on a body placed on a smooth horizontal table. If the force applied is 10N, find the total work done when the displacement of the body is 5m.

Step 1: Given dataForce applied (F) = 10NDisplacement of the body (s) = 5mHere angle between force and displacement is zero as they are parallel to each other hence θ=0°Step 2: Finding work doneWork =Fscosθ =10×5×cos0° =10×5×1=50JHence, the work done here is 50J

A horizontal force acts on a body placed on a smooth horizontal table. If the force applied is $10 N$ , find the total work done when the displacement of the body is $5 m$ .