CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A horizontal force F acts on a sphere of mass M at its centre. Coefficient of friction between the ground and sphere is μ. Let the maximum force F for which there is no slipping be n2μMg. Find n.

A
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 7
For linear motion, Ff=Ma.......(1)
and for rotational motion τ=Iα, for pure rolling a=Rα
fr=Iα
fr=25MR2×aR
f=25Ma
Ma=52f......(2)
Putting equation (2) in equation (1)
f=27F
For no slipping, fμMg
2F7μMg
F72μMg
Thus, n=7.

flag
Suggest Corrections
thumbs-up
13
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rolling
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon