Question

A horizontal force of $1.2kgwt$ is applied to a $1.5kg$ block resting on a horizontal surface $\mu =0.3,$ find the acceleration produced In the block.

Answer 1

Horizontal force

$F=1.2kgwt$

$F_1=1.2\times g$

Now frictional force

$F=umg$

$F=0.3\times 1.5\times g$

$F=0.45g$

Let acceleration produced in the body be $a$.

Now we have

$F_1-F=ma$

$1.2g-0.45g=1.5a$

$0.75g=1.5a$

$a=\frac{g}{2}$

$a=4.9m/s^2$