CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A horizontal force of 10.0 N is acting on a 10 kg box that is sliding to the right along the floor with velocity v (as depicted in the adjacent figure). The coefficient of kinetic friction between the box and the floor is 0.20. The box is moving with:-
133672_d6e6429f894a49cbbe71580ff7015462.png

A
acceleration to the left.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
acceleration to the right.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
constant speed and constant velocity.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
constant speed but not constant velocity.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A acceleration to the left.
Here friction force against the box motion is f=μmg=0.20×10×10=20N
As the friction force is greater than the 10 N force, the box will accelerate to left. The velocity or speed will decrease due to the friction.
149787_133672_ans_0c42e8cf47e34247b2f3fbb8bb1cef3c.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon