A horizontal force of 10N is necessary to just hold a block stationary against a wall as shown in the figure. The weight of the block is 2N. The coefficient of friction μ, between the block and the wall is
A
0.30
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B
0.20
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C
0.25
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D
0.35
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Solution
The correct option is B0.20 Given, the weight of the block W=2N and the applied external force to hold the block against wall F=10N The FBD of the block can be shown as
From the FBD of the block we have normal force as N=10N f=μN=μ×10=10μN Since, block is stationary with the wall, using ΣFy=0, we get f−W=0⇒f=W⇒10μ=2 ⇒μ=210=0.2