A horizontal force of $20 N$ is acting on the block which is at rest. Static friction acting on the block is

$0 N$

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$10 N$

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$20 N$

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$25 N$

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Solution

The correct option is C
$20 N$

Given,

Force acting $F$ = $20 N$

Since the block is at rest, the net force acting is zero. So frictional force of $20 N$ is acting on the block in the direction opposite to applied force.

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A horizontal force of 20 N is acting on the block which is at rest. Static friction acting on the block is

The correct option is C 20 N Given, Force acting F = 20 N Since the block is at rest, the net force acting is zero. So frictional force of 20 N is acting on the block in the direction opposite to applied force.

A horizontal force of $20 N$ is acting on the block which is at rest. Static friction acting on the block is

The correct option is C
$20 N$

Given,

Force acting $F$ = $20 N$

Since the block is at rest, the net force acting is zero. So frictional force of $20 N$ is acting on the block in the direction opposite to applied force.