A horizontal force of $500 N$ pulls two masses $10 K g$ and $20 K g$ (lying on a frictionless table) connected by a light string. What is the tension in the string? Does the answer depend on which mass end, the pull is applied?

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Solution

Let T be the tension on the string
500N force is applied its produce an acceleration a
500-T=20a eq(1)..
T= 10a eq(2)..
using this eq(1) and eq(2)
$a = \frac{50}{3}$

$T = \frac{500}{3}$
The tension in the string does not depend on the mass it only depends on force applied .

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A horizontal force of 500 N pulls two masses 10 Kg and 20 Kg (lying on a frictionless table) connected by a light string. What is the tension in the string? Does the answer depend on which mass end, the pull is applied?

Let T be the tension on the string 500N force is applied its produce an acceleration a500-T=20a eq(1)..T= 10a eq(2)..using this eq(1) and eq(2)a=503T=5003The tension in the string does not depend on the mass it only depends on force applied .

A horizontal force of $500 N$ pulls two masses $10 K g$ and $20 K g$ (lying on a frictionless table) connected by a light string. What is the tension in the string? Does the answer depend on which mass end, the pull is applied?

Let T be the tension on the string
500N force is applied its produce an acceleration a
500-T=20a eq(1)..
T= 10a eq(2)..
using this eq(1) and eq(2)
$a = \frac{50}{3}$

$T = \frac{500}{3}$
The tension in the string does not depend on the mass it only depends on force applied .