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Question

A horizontal overhead power line carries a current of 90 A in east towest direction. What is the magnitude and direction of the magneticfield due to the current 1.5 m below the line?

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Solution

Given: The current carried over power line is 90A, the distance of the point from the line is 1.5m.

Magnetic field at a point due to power line is given as,

B= μ 0 2I 4πr

where, the permeability of free space is μ 0 , current carried by the power line is I , and the distance of the point is r.

By substituting the given values in the above equation, we get,

B= 4π× 10 7 ×2×90 4π×1.5 =1.2× 10 5 T

Therefore, the magnetic field at a point due to power line is 1.2× 10 5 T. From right hand thumb's rule, the direction of the magnetic field at the observation point is towards the south.


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