A horizontal pipeline carries water in a streamline flow. At a point where the cross-sectional area is 10cm2, the water velocity is 1ms−1 and pressure is 2000Pa. The pressure of water at another point where the cross sectional area is 5cm2, is:
A
200Pa
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B
400Pa
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C
500Pa
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D
800Pa
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Solution
The correct option is C500Pa
Let the pressure be P at the second point and let velocity be v2=v Applying equation of continuity: A1v1=A2v2 10×1=5×v ⇒v=2ms−1 Apply Bernoulli's theorem at both the points, P1+12ρv21+ρgh=P2+12ρv22+ρgh [h= constant] ⇒2000+12×1000×12=P+12×1000×4 ∴P=500Pa