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Question

A horizontal pipeline carries water in a streamline flow. At a point where the cross-sectional area is 10 cm2, the water velocity is 1 ms1 and pressure is 2000 Pa. The pressure of water at another point where the cross sectional area is 5 cm2, is:

A
200 Pa
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B
400 Pa
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C
500 Pa
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D
800 Pa
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Solution

The correct option is C 500 Pa

Let the pressure be P at the second point and let velocity be v2=v
Applying equation of continuity:
A1v1=A2v2
10×1=5×v
v=2 ms1
Apply Bernoulli's theorem at both the points,
P1+12ρv21+ρgh=P2+12ρv22+ρgh
[h= constant]
2000+12×1000×12=P+12×1000×4
P=500 Pa

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