A horizontal straight wire 10 m long extending from east to west is falling with a speed of $5.0 m s^{- 1}$ , at right angles to the horizontal component of the earth's magnetic field 0.30 $\times 10^{- 4} W B m^{- 2}$ .(a) What is the instantaneous value of the emf induced in the wire?(b) What is the direction of the emf?(c) Which end of the wire is at the higher electrical potential?

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Solution

(a)
$l = 10 c m, v = 5.0 m / s, B = 0.3 \times 10^{- 4} W b m^{- 2}$
Induce EMF is $e = B l v = 1.5 \times 10^{- 3} V$

(b)
Using Fleming’s right hand rule, it can be inferred that the direction of the induced emf is from West to East.

(c)
The west end of the wire is at a higher potential.

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A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 m s⁻¹, at right angles to the horizontal component of the earth’s magnetic field, 0.30 × 10⁻⁴ Wb m⁻².

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(b) What is the direction of the emf?

Q. A horizontal straight wire 10 m long extending from east to west isfalling with a speed of 5.0 m s–1, at right angles to the horizontalcomponent of the earth’s magnetic field, 0.30 × 10–4 Wb m–2. (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?

Q. A

10 m

long horizontal wire extends from North East to South West. It is falling with a speed of

5.0 m s^{- 1}

, at right angles to the horizontal component of the earth's magnetic field, of

0.3 \times 10^{- 4} W b / m^{2}

. The value of the induced emf in wire is:

Q. A horizontal straight wire 10m long extending from east to west is falling with a speed of 5.0 m/s at right angles to the horizontal component of earth's magnetic field

0.3 \times 10^{- 4}

tesla. The emf induced across the ends of wire is

Q. A horizontal conducting rod

10

m long extending from east to west is falling with a speed

5.0 m s^{- 1}

at right angles to the horizontal component of the Earth's magnetic field,

0.3 \times 10^{- 4}

m^{- 2}

. Find the instantaneous value of the emf induced in the rod.

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(a)l=10 cm,v=5.0 m/s,B=0.3×10−4Wbm−2Induce EMF is e=Blv=1.5×10−3V(b)Using Fleming’s right hand rule, it can be inferred that the direction of the induced emf is from West to East.(c)The west end of the wire is at a higher potential.

(a)
$l = 10 c m, v = 5.0 m / s, B = 0.3 \times 10^{- 4} W b m^{- 2}$
Induce EMF is $e = B l v = 1.5 \times 10^{- 3} V$

(b)
Using Fleming’s right hand rule, it can be inferred that the direction of the induced emf is from West to East.

(c)
The west end of the wire is at a higher potential.