Question

A horse exerts a force of $99.47N$ to pull the cart. If the horse-cart system moves with a velocity $27km{h}^{-1}$ on the level road, then find the power of the horse in terms of horsepower. $\left(1hp=746W\right)$

Answer 1

Step 1: Data provided,

$$\begin{gathered} Force\left(F\right)=99.47N \\ velocity\left(v\right)=27km{h}^{-1} \\ Convertingkm/hinm/s \\ \frac{5}{18}\times 27m{s}^{-1}=7.5m{s}^{-1} \end{gathered}$$

Step 2: Formula used,

$Power\left(P\right)=Force\left(F\right)\times velocity\left(v\right)$

Step 3: Calculation,

$$\begin{gathered} Power\left(P\right)=Force\left(F\right)\times velocity\left(v\right) \\ =99.47N\times 7.5m{s}^{-1} \\ =746.025W \\ 1hp\simeq 746W \\ =\frac{746}{746}hp=1hp \end{gathered}$$

Hence, the power of the horse is 1 hp.