Question

A horse is tied to a pole fixed at one corner of a $30m\times 30m$ square field of grass by a $10m$ long rope. $(\pi =3.14)$ So what will be the area of the field in which the horse can graze, if the pole was fixed at the middle of the side?

Answer 1

In this case, the area of the field in which the horse can graze is one half of the circle of radius $=10m$
Area of a circle $=\pi r^2$

Hence, area of the field in which the horse can graze $=\frac{1}{2}\times \frac{22}{7}\times 10\times 10=157.15$ sq m