Question

A hot liquid contained in a container of negligible heat capacity loses temperature at rate 3K/min,just before it begins to solidify.The temperature remains constant for 30min . Find ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 (given that rate of losing heat is constant)

Answer 1

Dear student

let mass be m
specific heat capacity be c
and latent heat of fusion be L

Let Q be the heat change

Q can be found out by the rate give

Q=3 x 30 K=90 K

Q= mct=90 t is temp change

t= 90/mc K


Now,

L=Q/m
or, L=(90/mc)/m
or, L/c= 90 K

or, c/L= 1/90 in K^-1

​Regards