A hot liquid is kept in a big room. The logarithm of the numerical value of the temperature difference between the liquid and the room is plotted against time. The plot will be very nearly
A
a straight line
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B
a circular arc
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C
a parabola
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D
an ellipse.
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Solution
The correct option is A a straight line
By newton's law of cooling formula,
dTdt=k[T−Tm]⇒dTT−Tm=kdt
On integrating,
⇒∫dTT−Tm=k∫dt⇒ln[T−Tm]=kt+C
So, from above equation; ln[T−Tm]∝t
If graph is plotted between ln[T−Tm] and t, the graph will be straight line.