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Heat

A hot object ...

Question

A hot object with a temperature $T_{1}$ is connected to a cool object with a temperature of $T_{2}$ . The object used to conduct heat has a length L and a cross-sectional area A. The rate of heat flow is :

A

A (T_{1} - T_{2}) / k L

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B

k (T_{1} - T_{2}) / A L

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C

k A L / (T_{1} - T_{2})

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D

k A (T_{1} - T_{2}) / L

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Solution

The correct option is D $k A (T_{1} - T_{2}) / L$
Rate of heat flow is given by
$\frac{Q}{L} = \frac{k A (T_{1} - T_{2})}{L}$ (for heat flow through conduction)
where $k$ = thermal conductivity of material
$A$ = cross-selectional area
$L$ = Length
$△ T = T_{1} - T_{2} =$ change in temperature

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