Question

A house worth Rs. 9000 is sold by Mr.$A$ to Mr. $B$ at a 10% loss Mr. $B$. sells the house back Mr. $A$ at a 10% gain. The result of the two transactions is :

• A. Mr $A$ breaks even
• B. Mr. $B$ gains Rs. 900
• C. Mr. $A$ loses Rs. 900
• D. Mr. $A$ loses Rs. 810
• E. Mr. $B$ gains Rs. 1710

Answer 1

Answer: (D)

Mr. $A$ loses Rs. 810

Selling Price of house to Mr. B = $(1-\frac{10}{100})9000=8100$ Rs

Selling Price of house to Mr. A = $(1+\frac{10}{100})8100=8910$ Rs

$\therefore$ A sells at Rs. 8100 and bought at Rs. 8910.

$\therefore$ Mr. A loses = 8910 - 8100 = Rs 810