(a) Process to achieve AM:
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/8210/content_12_1.png)
Here the modulating signal
Am sin ωmt is added to the carrier signal
Am sin ωmt to produce the signal x(t). This signal
x(t)=Am sinωct is passed through a square law device which is a non- linear device which produces an output
y(t)=Bx(t)+Cx2(t) Where B and C are constant, Thus,
y(t)=BAmsin ωmt+BAcsin ωct +C[A2msin2 ωmt+A2csin2 ωct+2AmAcsinωmtsinωct]...(ii)=BAmsinωmt+BAcsinωct+CA2m2+C2A2c−CA2m2cos 2ωmt−CA2c2cos 2ωct+CAmAccos(ωc−ωm)t−CAmAccos(ωc+ωm)t...(iii) In equation (iii) , there is a dc term
C/2(A2m+A2c) and sinusoids of frequencies
ωm,2ωm,ωc,2ωc,ωc−ωm and
ωc+ωm. As shown in the above figure , this signal is passed through a band pass filter which rejects dc, the sinusoids of frequencies
ωm,2ωm,2ωc and retains the frequencies
ωc,ωc−ωm and
ωc+ωm. The output of the band pass filter is an AM wave.
(b) Given :
fc+fm=660 (i)fc+fm=640 (ii) Adding (i) and (ii),
2fc=1300fc=650khz Putting in (i),
fm=660−650 fm=10khz Bandwidth =
2fm =2×10 = 20 kHz