1
Question
(a) How will you convert the following:
(i) Propanone to Propan −2−ol
(ii) Ethanal to 2−hydroxy propanoic acid
(iii) Toluene to benzoic acid
(b) Given simple chemical test to distinguish between:
(i) Pentan-2-one and Pentan−3−one
(ii) Ethanal and Propanal
(i) Propanone to Propan −2−ol
(ii) Ethanal to 2−hydroxy propanoic acid
(iii) Toluene to benzoic acid
(b) Given simple chemical test to distinguish between:
(i) Pentan-2-one and Pentan−3−one
(ii) Ethanal and Propanal
Open in App
Solution
(a)i) Propanone to Propan-2-olOOH|||CH3−C−CH3Na/alcohol−−−−−−−→CH3−CH−CH3
ii) Ethanal to 2-Hyroxypropanoic acidH|CH3−C=OH+.CN−−−−−→H|CH3−C−OHH+H2O−−−−−→|CNOH|CH3−CH−COOH
iii) Toluene to benzoic acid (ref. image )
(b)i) Pentan-2-one and Pentan-3-oneO||CH3−C−CH2−CH2−CH3 and O||CH3−CH2−C−CH2−CH3
By Iodoform TestPentan-2-one being a methyl ketone when treated with NaOl (I2/NaOH) gives yellow precipitate of iodoform but pentan-3-one does
O||CH3−CH2−CH2pentan−2−ene−C−CH3+3NaOI→CH3CH2CH2COONa+CHI3↓Iodoform(yellowppt)+2NaOH
O||CH3−CH2−CPentan−3−ene−CH2−CH3NaOI−−−→No yellow precipitate of CHI3
ii) Ethanal and PropanalO||CH3−C−H and O||CH3−CH2−C−H
By Iodoform test
i) Propanone to Propan-2-ol
OOH|||CH3−C−CH3Na/alcohol−−−−−−−→CH3−CH−CH3
ii) Ethanal to 2-Hyroxypropanoic acid
H|CH3−C=OH+.CN−−−−−→H|CH3−C−OHH+H2O−−−−−→|CNOH|CH3−CH−COOH
iii) Toluene to benzoic acid (ref. image )
(b)
i) Pentan-2-one and Pentan-3-one
O||CH3−C−CH2−CH2−CH3 and O||CH3−CH2−C−CH2−CH3
By Iodoform Test
Pentan-2-one being a methyl ketone when treated with NaOl (I2/NaOH) gives yellow precipitate of iodoform but pentan-3-one does
O||CH3−CH2−CH2pentan−2−ene−C−CH3+3NaOI→CH3CH2CH2COONa+CHI3↓Iodoform(yellowppt)+2NaOH
O||CH3−CH2−CPentan−3−ene−CH2−CH3NaOI−−−→No yellow precipitate of CHI3
ii) Ethanal and Propanal
O||CH3−C−H and O||CH3−CH2−C−H
By Iodoform test
Suggest Corrections
0
Similar questions