A human population containing $200$ individuals has two alleles at the 'T' locus, named T & t. T, which produces tall individuals, is dominant over t, which produces short individuals. If the population has $90$ TT, $40$ Tt, and $40$ tt genotypes, what will be the frequencies of these two alleles in this population?

T, 0.50; t, 0.50

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T, 0.55; t, 0.45

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T, 0.45; t, 0.35

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T, 0.90; t, 0.10

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Solution

The correct option is B $T, 0.55; t, 0.45$

frequency = no. of individuals with allele distribution/total no. of individuals
t $^{2}$ = 40/200 = 1/5

t = 0.4472 = 0.45

as we know , T + t = 1

T = 1-0.45

T = 0.55

So, correct answer to the question is 'T=0.55, t=0.45'.

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The correct option is B T,0.55;t,0.45 frequency = no. of individuals with allele distribution/total no. of individuals t2 = 40/200 = 1/5 t = 0.4472 = 0.45 as we know , T + t = 1 T = 1-0.45 T = 0.55 So, correct answer to the question is 'T=0.55, t=0.45'.

The correct option is B $T, 0.55; t, 0.45$

frequency = no. of individuals with allele distribution/total no. of individuals
t $^{2}$ = 40/200 = 1/5

t = 0.4472 = 0.45

as we know , T + t = 1

T = 1-0.45

T = 0.55

So, correct answer to the question is 'T=0.55, t=0.45'.