Question

A husband and his wife appear in an interview for two vacancies. The probability of their selection are respectively 1/4 and 1/3. What is the probability that only one of them will be selected?

• A. 5/11
• B. 5/12
• C. 5/13
• D. 5/14

Answer 1

The correct option is B 5/12

Let A be the event of husband getting selected.

P(A) = 1/4

P( not A) = 3/4

Let B be the event of wife getting selected.

P(B) = 1/3

P( not B) = 2/3

Now let E be the event of one of them getting selected

Therefore,

P(E) = P(A) P( not B) + P(B) P( not A)

= 1/4 x 2/3 + 1/3 x 3/4

= 5/12