Question

A husband and wife appeared for the interview of the same posts. If the probability of the husband selected is 1/7 and that of the wife is 1/5. The probability of both of them selected is........

• A. $1/35$
• B. $4/35$
• C. $1/10$
• D. $12/35$

Answer 1

Answer: (A)

$1/35$

Let A= event that the husband is selected.

and B = event that the wife is selected.

Then given, $P\left(A\right)\frac{1}{7},P\left(B\right)=\frac{1}{5}$

Therefore, the required probability of both of them selected = P(A and B)

$⟹P\left(A\right).P\left(B\right)=\frac{1}{7}\times \frac{1}{5}=\frac{1}{35}$