Question

(a) Hybridisation of Be in $Be{F}_2$ is $sp$.

(b) When ${BeF}_4^{2-}$ is formed hybridisation of Be changes from $sp$ to $s{p}^3$.

• A. Both (a) and (b) are correct.
• B. Both (a) and (b) are inorrect.
• C. (a) is correct and (b) is incorrect.
• D. (a) is incorrect and (b) is correct.

Answer 1

Answer: (A)

Both (a) and (b) are correct.

(a) Hybridisation of Be in $Be{F}_2$ is $sp$ (2 sigma bonds are there).

(b) When ${BeF}_4^{2-}$ is formed hybridisation of Be changes from $sp$ to $s{p}^3$. (4 sigma bonds are there).

So, both the statements are correct.

Hence option Ais correct.