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Percentage Composition

A hydrate of ...

Question

A hydrate of $N a_{2} S O_{3}$ has $50 %$ water by mass. It is :

N a_{2} S O_{3} \cdot 4 H_{2} O

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N a_{2} S O_{3} \cdot 6 H_{2} O

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N a_{2} S O_{3} \cdot 7 H_{2} O

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N a_{2} S O_{3} \cdot 2 H_{2} O

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Solution

The correct option is A $N a_{2} S O_{3} \cdot 7 H_{2} O$
$N a_{2} S O_{3} : H_{2} O \equiv 50 : 50$ by mass (Molecular weight of $N a_{2} S O_{3} = 126)$
Number of moles $= \frac{50}{126} : \frac{50}{18}$
$∴ R a t i o = 1 : 7$
Hence, the compound is $N a_{2} S O_{4} .7 H_{2} O$ .

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