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A hydraulic l...

Question

A hydraulic lift at a service station can lift cars with a mass of $3500 k g$ . The area of cross section of the piston carrying the load is $500 c m^{2}$ . What pressure does the smaller piston experience? $g = 9.8 m / s^{2} .$

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Solution

Pressure = $\frac{F o r c e}{A r e a} = \frac{3500 \times 9.8}{500 \times 10^{- 4} N / m^{2}} = 6.86 \times 10^{5} N / m^{2}$

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