A hydraulic lift is used to lift a car of mass 3000 kg- The cross-sectional area of the lift on which the car is supported is 5- 10-2m- What is the pressure on the smaller piston- if both the pistons are at the same horizontal level-Take g - 10 ms-2-

The radius of the #34;Smaller piston #160; #34; is not given here so we have to assume that both pistons are identical. So, m=3000 kg, A= 5×10^ 2 T ...

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Standard XII

Physics

Pascal's Law

A hydraulic l...

Question

A hydraulic lift is used to lift a car of mass $3000 k g$ . The cross-sectional area of the lift on which the car is supported is $5 \times 10^{- 2} m$ . What is the pressure on the smaller piston, if both the pistons are at the same horizontal level?
Take $g = 10 m s^{- 2}$ .

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Solution

The radius of the "Smaller piston " is not given here so we have to assume that both pistons are identical. So, m=3000 kg, A= $5 \times 10^{- 2}$
Therefore $F = m g = 3000 \times 10 = 30, 000 N$
Therefore, assuming both pistons are identical and on the same horizontal height, pressure on each piston = $\frac{F}{2 A} = 3, 00, 000 N / m^{2}$

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A hydraulic lift is used to lift a car of mass 3000 kg. The cross-sectional area of the lift on which the car is supported is 5×10−2m. What is the pressure on the smaller piston, if both the pistons are at the same horizontal level?Take g=10 ms−2.

The radius of the "Smaller piston " is not given here so we have to assume that both pistons are identical. So, m=3000 kg, A= 5×10−2ThereforeF=mg=3000×10=30,000NTherefore, assuming both pistons are identical and on the same horizontal height, pressure on each piston =F2A=3,00,000N/m2

A hydraulic lift is used to lift a car of mass $3000 k g$ . The cross-sectional area of the lift on which the car is supported is $5 \times 10^{- 2} m$ . What is the pressure on the smaller piston, if both the pistons are at the same horizontal level?
Take $g = 10 m s^{- 2}$ .