A hydraulic structure has four gates which operate independently. The probability of failure of each gate is 0.2. Given that gate 1 has failed, the probability that both gates 2 and 3 will fail is
A
0.240
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B
0.200
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C
0.040
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D
0.008
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Solution
The correct option is C 0.040 The required probability = (Prob. of failure of gate 2) × (Prob. of failure of gate3)